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49x=-x^2
We move all terms to the left:
49x-(-x^2)=0
We get rid of parentheses
x^2+49x=0
a = 1; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·1·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*1}=\frac{-98}{2} =-49 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*1}=\frac{0}{2} =0 $
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